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bit of a Friday moment with some SQL

Christopher Hill
$organization



Hia all

 

I am having a bit of a Friday moment with some SQL and am hoping someone can show me the light…??

I am sure its very basic – but the finer details are some what eluding me today…

 

I have this script equivalent…

 

            Select

                        B.Description

                        Count(B.Description)

                        Sum(A.Amount)

            From

                        Table1 A

                        Join Table2 B on (A.id = B.id)

 

Where table A has one to many records of table B.

 

This runs fine, but what I am seeing is an incorrect Sum amount due to this one to many association between the two tables.

i.e. if an ID from Table A has £5 in the Amount column, and the same ID exists on 4 records on Table B – my sum result is coming back at £20, I only want a distinct £5.

 

My initial thought was to do something like putting Distinct in front of the A.Amount (Sum(Distinct A.Amount)) within the aggregate, but this groups by the money values, and not the ID…

 

I hope that makes sense to someone out there?!

Many thanks in advance!!

 

Christopher Hill

Swyddog Dadansoddi a Chymorth SQL

SQL Support Analyst

Canolfan Mileniwm Cymru

Wales Millennium Centre

 

Ebost\Email Christopher.Hill@wmc.org.uk

Ffon\Tel 029 2063 6372

 

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[edited by: Todd Lantry at 1:44 PM (GMT -6) on 20 Jul 2009] added subject to post TL
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  • $organization
    I will be out of the office starting 07/17/2009 and will not return until
    07/20/2009.

    I will respond to your message when I return.
  • Former Member
    Former Member $organization in reply to Jan LaRocque

    I  am trying to write a custom procedure and I know my question can easily be answered by some of you SQL gurus out there…

     

    Here is the code I have so far:

     

    select  cc.customer_no, cc.constituency, ct.description, ct.short_desc,

    c.fname, c.lname, st.department, st.title, st.hire_date, st.end_date, st.status

    from tx_const_cust cc

    join t_customer c

    on c.customer_no = cc.customer_no

    join tr_constituency ct

    on ct.id = cc.constituency

    join lt_MCFTA_STAFF st

    on st.customer_no = c.customer_no

    where cc.constituency in (48,49,50)

    and st.status = 'Active'

    order by c.lname

     

     

    I want to add in a CASE statement, so that the code pulls fname and lname when the n1n2_ind = 1, but pulls fname2 and lname2 instead, when the n1n2_ind = 2.  I am guessing I need something like the below, but am not sure how to format and where to insert the new code into the above statement:

     

    CASE c.fname, c.lname

    Where cc.n1n2_ind = 1

     

    ELSE c.fname2. c.lname2

    Where cc.n1n2_ind = 2

     

    Thanks in advance for help!

     

  • $organization in reply to Former Member

    Penny -

    Try this on for size:

    select  cc.customer_no, cc.constituency, ct.description, ct.short_desc,

    c.fname, c.lname, st.department, st.title, st.hire_date, st.end_date, st.status,

    CASE WHEN cc.n1n2_ind = 2 THEN 

    c.fname2 +', ' + c.lname2

    ELSE c.fname +', ' + c.lname

    END as full_name

    from tx_const_cust cc

    join t_customer c

    on c.customer_no = cc.customer_no

    join tr_constituency ct

    on ct.id = cc.constituency

    join lt_MCFTA_STAFF st

    on st.customer_no = c.customer_no

    where cc.constituency in (48,49,50)

    and st.status = 'Active'

    order by c.lname

    HTH,
    Heather

Reply
  • $organization in reply to Former Member

    Penny -

    Try this on for size:

    select  cc.customer_no, cc.constituency, ct.description, ct.short_desc,

    c.fname, c.lname, st.department, st.title, st.hire_date, st.end_date, st.status,

    CASE WHEN cc.n1n2_ind = 2 THEN 

    c.fname2 +', ' + c.lname2

    ELSE c.fname +', ' + c.lname

    END as full_name

    from tx_const_cust cc

    join t_customer c

    on c.customer_no = cc.customer_no

    join tr_constituency ct

    on ct.id = cc.constituency

    join lt_MCFTA_STAFF st

    on st.customer_no = c.customer_no

    where cc.constituency in (48,49,50)

    and st.status = 'Active'

    order by c.lname

    HTH,
    Heather

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