Counting unique individuals for which tickets are purchased at a multi-venue General Admission destination

Hello:

We are a multi venue general admission destination as the questions hints. I'm trying to find a way in analytics to determine (approximately) the number of unique ticketed individuals an order or collection of orders represent. For example,an individual order could include:

  • 3 tickets for the castle
  • 2 for the tower
  • 2 for one of the galleries.

Whilst this could represent tickets for anything from 3 to 7 separate individuals, a reasonably safe assumption is that it is 3 individuals, but one of them has decided not to go tower and has no interest in art. I'm struggling to find a way in analytics to aggregate ticket counts per line to return just the maximum number of tickets on any 1 line in the order (which then I could sum per month, etc) so that I can then use my assumption. As anyone with the same issue solved this?

We do offer packages that are easier to work out, but many tickets sales are still individual tickets. We also don't yet have NSCAN - so stuck trying to solve it as above.

Thanks,

Bob.

Parents
  • Thanks Chris.
     
    The way I had worked fine in a pivot whereby was showing each order on a line, but if you then applied a further aggregation (say grand total, or just used formula in an indicator) it would return the single highest ticket count, not a sum of what was shown in pivot. Make sense I think if I now understand it properly.
     
    Think your suggestion should allow be to sum the set of maxes. Will try.
     
    Thanks again.
     
    Bob.
     
Reply
  • Thanks Chris.
     
    The way I had worked fine in a pivot whereby was showing each order on a line, but if you then applied a further aggregation (say grand total, or just used formula in an indicator) it would return the single highest ticket count, not a sum of what was shown in pivot. Make sense I think if I now understand it properly.
     
    Think your suggestion should allow be to sum the set of maxes. Will try.
     
    Thanks again.
     
    Bob.
     
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